x(x-4)=x^2+2x+5

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Solution for x(x-4)=x^2+2x+5 equation:


Simplifying
x(x + -4) = x2 + 2x + 5

Reorder the terms:
x(-4 + x) = x2 + 2x + 5
(-4 * x + x * x) = x2 + 2x + 5
(-4x + x2) = x2 + 2x + 5

Reorder the terms:
-4x + x2 = 5 + 2x + x2

Add '-1x2' to each side of the equation.
-4x + x2 + -1x2 = 5 + 2x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-4x + 0 = 5 + 2x + x2 + -1x2
-4x = 5 + 2x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-4x = 5 + 2x + 0
-4x = 5 + 2x

Solving
-4x = 5 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
-4x + -2x = 5 + 2x + -2x

Combine like terms: -4x + -2x = -6x
-6x = 5 + 2x + -2x

Combine like terms: 2x + -2x = 0
-6x = 5 + 0
-6x = 5

Divide each side by '-6'.
x = -0.8333333333

Simplifying
x = -0.8333333333

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